Seraphina is driving two hours to visit her family. for the first hour, she traveled at a speed of 61 miles per hour. then, in the second hour, she traveled at a speed of 72 miles per hour. what is the percentage increase of seraphina's speed?

The percentage increase of Seraphina's speed=18.033%

Step-by-step explanation:

Step 1

Define the initial and final speeds as shown;

Initial speed=61 miles per hour

Final speeds=72 miles per hour

Step 1

Express the formula for calculating the percentage increase of Seraphina's speed as follows;

% increase={(F-I)/I}×100

where;

F=final speed

I=initial speed

In our case;

F=72 miles per hour

I=61 miles per hour

replacing;

% increase={(72-61)/61}×100

% increase=(11/61)×100=18.033%

The percentage increase of Seraphina's speed=18.033%

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: