There are 26 students in mrs. ortlieb’s class. there are two more boys than girls. solve a system of equations that represents the situation.

There are 14 boys and 12 girls

Step-by-step explanation:

There are 26 students in Mrs. Ortlieb's class.

There are two more boys than girls.

Let the number of boys be x and number of girls be y.

x + y = 26 ... (i)

x = 2 + y ... (ii)

Solving this system of simultaneous equations by rearranging first:

x + y = 26 ... (i)

x - y = 2 ... (ii)

Adding (i) and (ii) gives;

2x + 0 = 28

x = 28 ÷ 2 = 14

So there are 14 boys and;

26 - 14 = 12 girls.

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

2 is the final ! : )