Asurvey asked students whether they have any siblings and pets. the survey data are shown in the relative frequency table. given that a student does not have a sibling, what is the likelihood that he or she has a pet?

The likelihood that he or she has a pet given that a student does not have a sibling is:

Option: D ( 60%)

Step-by-step explanation:

Let A denote the event that a student does not have a sibling.

Let B denote the event that a students has a pet.

Then A∩B denotes the event that the student does not have a sibling but has a pet.

Let P denote the probability of an event.

Then, we are asked to find:

P(B|A)

We know that:

Also from the table we have:

P(A)=0.25

and P(A∩B)=0.15

Hence,

which in percentage is:

Hence, the likelihood is:

60%

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .