Given f'(x) = (x-4)(4-2x), find the x-coordinate for relative maximum on the graph of f(x)

The coordinate of the relative maximum is x=4.

Step-by-step explanation:

Given that the derivative of the function is , the maxima and minima or the critical points can be found where that is:

The solutions to this equation are and

Now, if the second derivative for a function  is negative at a critical point, then the critical point is the relative maximum.

Therefore we want to see at which of the two critical points is negative. The second derivative is:

Now is , and is , therefore we deduce that the relative maxium is located at , because there the second derivative is negative.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.