If chris has 4 times as many nickels as quarters and they have a combined value of 180 cents, how many of each coin does he have?

1 nickel = 5 cents

1 quarter = 25 cents

Let the number of nickels be = n

Let the number of quarters be = q

As mentioned, Chris has 4 times as many nickels as quarters

so, n=4q ----- (1)

The coins have a combined value of 180 cents, so

  ----- (2)

Putting n=4q in equation (2)

Hence, quarters are 4

As, n=4q

Hence, nickels are 16

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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