2. a lunch stand makes s.75 profit on each chef's salad and $1.20 profit on each caesar salad. on a typical weekday, it sells between 40 and 60 chef's salads and between 35 and 50 caesar salads. the total number sold has never exceeded 100 salads. how many of each type should be prepared in order to maximize profit? could you make a graph as the answer?

Let's let

x = the number of chef salads, x>=0

y = the number of Caesar salads, y>=0

The constrains are:

40 <= x <= 60

35 <= y <= 50

x + y <= 100

The objective function here is F(x, y) = 0.75x + 1.20y

The corner points are (40, 35),  (60, 35), (60, 40), (50, 50) and (40, 50).

F (40, 35) = 0.75*40 + 1.20*35 = $72

F (60, 35) = 0.70*60 + 1.20*35 = $84

F (60, 40) = 0.75*60 + 1.20*40 = $93

F (50, 50) = 0.75*50 + 1.20*50 = $97.50

F (40, 50) = 0.75*40 + 1.20*50 = $90

Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.