Find the equation of the line that is perpendicular to the line y = (-1/3)x -1 and passes through the point (1, 5)? here is what i have so far y= (-1/3)x - 1 5= (-1/3)*1 -1 5 =

bearing in mind that perpendicular lines have negative reciprocal slopes, so

so we're really looking for a line whose slope is 3 and runs through (1,5)

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

a .4y4

hope this !