In 20 l of air, there is about 0.78 l of carbon dioxide. about how many liters of carbon dioxide are there in 1 l of air?

So for this we will be setting up a proportion. Since we know that for 20 L of air there is 0.78 L of CO₂, we can determine that for 1 L of air there is X L of CO₂ . We can set that up as such:

From here we can solve for x. Firstly, cross-multiply:

Next, divide both sides by 20:

For 1 L of air, there is 0.039 L of CO₂

i can't read the graph

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)