What is the slope and equation of the line?

3 is your slope; y = 3x - 2 is your equation

Step-by-step explanation:

Find the slope. Note the slope-formula: slope = (y₂ - y₁)/(x₂ - x₁)

Set the points:

(x₁ , y₁) = (1 , 1)

(x₂ , y₂) = (2 , 4)

Set the corresponding numbers to the corresponding variables

slope = (y₂ - y₁)/(x₂ - x₁)

slope = (4 - 1)/(2 - 1)

Simplify. Remember to follow PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction)

slope = (4 - 1)/(2 - 1)

slope = (3)/(1)

3/1 is your slope

Note that the slope-intercept form is: y = mx + b

Plug in 3 for slope, and use a point (in this example: (1, 1)

Plug in 3 for slope, or m

Plug in 1 for x, and 1 for y

1 = (3)1 + b

Simplify. Combine like terms

1 = 3 + b

Isolate the variable. Note the equal sign, what you do to one side, you do to the other. Subtract 3 from both sides

1 (-3) = 3 (-3) + b

b = 1 - 3

b = -2

You're Equation of the line is: y = 3x - 2

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entering that problem on the tube might get you an answer