Paige borrows $4000 at a rate of 12% interest per year. what is the amount due at the end of 3 years if the interest is compounded continuously? $4,480 $5733.31 $5,733.32 $5,440

$5733.32

Step-by-step explanation:

Use this formula for continuous compounding:

A = Pe^(r*t), where P is the principal amount, r is the interest rate as a decimal fraction, and t is the number of years.

Then:

A = $4000e^(0.12*3) = $5733.32

is this a multiple choice question?

if so it's a and c

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b