Points a, b, and c are midpoints of the sides of right triangle def. which statements are true? check all that apply. (the formula for the area of a triangle is a = bh.) bc = 6 cm ac = 5 cm ba = 4 cm the perimeter of triangle abc = 12 cm. the area of triangle abc is the area of triangle def.

Given: A right triangle DEF, in which A, B,C are mid points of DE , EF, and FD respectively. BC=6 cm, AC= 5 cm, BA=4 cm

Solution:

1. Perimeter of triangle ABC=AB+BC+CA=6+5+4=15 cm

But it is given that perimeter of triangle ABC is 12 cm.So, this is incorrect statement.

2. As we know line segment joining the mid point of two sides of triangle is parallel to third side and is half of it.

AB║DF and AB=1/2 DF, BC║DE and BC=1/2 DE, AC║EF,and AC=1/2EF

∴Quad.ABCF, Quad.CBAE, Quad.DABC is a parallelogram, and diagonal of parallelogram divides it into two congruent triangles.

ΔABC≅ΔBCF≅DAC≅ABE

Area(ΔDEF)=4×Area(ΔABC)

→ Area of triangle ABC to area of triangle DEF is 1/4.

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)