Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. write the polynomial in standard form? 7, -11, and 2 + 8i f(x) = x4 - 9x3 - 56x2 + 290x - 5236 f(x) = x4 - 9x3 + 56x2 - 290x + 5236 f(x) = x4 - 145x2 + 580x - 5236 f(x) = x4 - 25x2 + 580x - 5236

We are given zeros of the polynomial : 7, -11, and 2 + 8i.

Note: The radical zero always comes with the pair of plus and minus sign.

Therefore, another zero would be 2-8i.

Now, in order to find the polynomial with the zeros 7, -11, 2 + 8i and 2-8i, we need to find the factors of the polynomial.

The factors of the polynomial would be (x-7)(x+11)(x-2-8i)(x-2+8i).

Let us multiply those factors to get the standard form of the polynomial.

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2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.