15 points! a line goes through the points (7,8) and (3, 10). a) what is the slope of the line? show your work. b) write the equation of the line in point-slope form. show your work c) write the equation of the line in slope-intercept form. show your work.

Hi there! You are provided with two points, this is all you need to calculate the line's slope.

The equation for slope is:

Slope: -2/4

Point slope form, or y-y1 = m(x - x1). All we have to do is take the x and y coordinates of either point, as well as the slope, and plug them into the equation.

y - 10 = -2/4(x - 3)

Write the equation in slope-intercept form (y=mx+b)

A) -2/4

B) y - 10 = -2/4(x - 3)

C) y = -2/4x + 11.5

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50