What is the axis of symmetry of y= -(x+10)^2-9

Y=×^2-9

Step-by-step explanation:

(X+0)^2-9

Use the vertex form, y=a(x-h)^2+k

a=1

h=0

k=-9

And because the parabola opens up the vertex is (0,-9)

The distance from the vertex to a focus of the parabola by using the __ 1/4a__ formula:

1/4(1)

1/4

(h,k+p)

(0,-35/4)

y > 1/3x

y < = -x + 4

hope this : )