Need ! in △abc, the coordinates of vertices a and b are a(1,2) and b(-3,-1). for each of the given coordinates of vertex c, is △abc a right triangle? select right triangle or not a right triangle for each set of coordinates. c(-3,-2) c(0,-5) c(1,-2)

None of them are right triangles.

Hope This Helps!!!

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

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