The sum of three numbers is 81.the first number is 11 less than the second. the third number is 6 more than twice the first. what is the largest of the three numbers?

n - the first number

n + 11 - the second number

2n + 6 - the third number

81 - the sum of three numbers

The equation:

n + (n + 11) + (2n + 6) = 81

n + n + 11 + 2n + 6 = 81     combine like terms

(n + n + 2n) + (11 + 6) = 81

4n + 17 = 81      subtract 17 from both sides

4n = 64       divide both sides by 4

n = 16

the largest of the tree numbers is the third number 2n + 6.

Substitute the value of n:

2(16) + 6 = 32 + 6 = 38

the answer is d

step-by-step explanation: