Ff 5x2 + y4 = 21 then evaluate the second derivative of y with respect to x when x = 2 and y = 1. round your answer to two decimal places. use the hyphen symbol, -, for negative values. answer asap

It is given that ,

Differentiating both sides with respect to x, we get

→4 y³ y' = 0 - 10 x , where y' is first derivative of y w.r.t  x.

→4 y³ y' =  - 10 x

When x=2, y=1, substituting these values in above equation

→4× 1³×y'= -10×2

→ y'= -20/4= -5

Differentiating again w.r.t  x,the above equation we get

→4 [ 3 y²y'² + y³ y''] = -10 where y'' is double derivative of y w.r.t x.

→3 y²y'² + y³ y'' = -10/4= -5/2

Substituting x=2, y=1, y'= -5,in above equation we get

→ 3 ×1²×(-5)² + 1³× y'' = -5/2

→  75 + y'' = -5/2

→ y''= -5/2 - 75

→ y'' =

→ y''=  -77.50(Answer)

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.