How to find the minimum value of f(x) = 3x (x - 4)?

well, let's first off, expand the expression, 3x(x-4) => 3x²-12x, which we can also write as

f(x) = 3x² - 12x + 0

now, this is a quadratic equation with a leading term with a positive coefficient, namely its graph is a parabola, or a Cup-Shaped figure, so the graph comes from the top, goes down down down, reaches a U-turn, then goes back up up up.

the U-turn, or vertex of the quadratic, is the lowest point in the "cup".

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

i think it is 70

step-by-step explanation: