1. what are the domain restrictions of q^2−7q−8/q^2+3q−4 q≠1 and q≠−8 q≠−1 and q≠4 q≠1 and q≠−4 q≠−1 and q≠8 2. what are the domain restrictions of the expression y^2−3y−40/y^2+9y+20 ? y≠−5 y≠8 y≠4 y≠−4 y≠5 y≠−8

(1)

we are given

We know that any function is undefined when denominator =0

so, we will set denominator =0

and then we can solve for q

now, we can factor it

so,

q≠1 and q≠−4............Answer

(2)

we are given

Since, any function is undefined when denominator =0

so, we set denominator =0

and then we can solve for y

so,

y≠−5

y≠−4.............Answer

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

i think the answer is fried chicken ; >

step-by-step explanation: