Consider the figure below. abraham cut regular pentagon abcde into quadrilateral begc. which of the following statements is true about quadrilateral begc? (picture included)

Let 'n' be the number of side of a regular polygon each angle are equal and sum of  each angle equal to (n-2)×180. ∴For a regular pentagon have five equal side, n=5 ∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108° Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio Therefore ∠ABE : ∠CBE = 36: 72∴ ∠GCB + ∠CBE = 108° +72°=180°

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b

answer: 30

step-by-step explanation: its 30 because im a basketball player and stephen curry hits most of his shots so if you put 30 you might make the shot goodluck