Three consecutive odd integers are such that the sum of the first and second is 31 less than 3 times the third. find the integers (urgent)

Using a system of equations, it is found that the integers are 21, 23 and 25.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the three consecutive odd integers are:

n, n + 2 and n + 4.

The sum of the first and second is 31 less than 3 times the third, hence:

n = 21

n + 2 = 23

n + 4 = 25

Hence the integers are 21, 23 and 25.

More can be learned about a system of equations at link

1st:x

2nd x+2

3rd: x+4

(x)+(x+2) = 3(x+4)-31

distribute

2x+2 = 3x+12-31

2x+2 =3x-19

subtract 2x from each side

2 = x-19

add 19 to each side

21 =x

21,23,25

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.