Can someone me with algebraic method

x = -8; y = 0

Step-by-step explanation:

x + 2y = -8

3x - 4y = -24

We will use the substitution method.

Solve the first equation for x.

x = -8 - 2y

Replace x of the second equation with -8 - 2y, and solve for y.

3x - 4y = -24

3(-8 - 2y) - 4y = -24

-24 - 6y - 4y = -24

-24 - 10y = -24

-10y = 0

y = 0

Now we substitute 0 for y in the first original equation and solve for x.

x + 2y = -8

x + 2(0) = -8

x + 0 = -8

x = -8

Solution: x = -8; y = 0

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

kayla would of sent 8

step-by-step explanation: