Given: △abc, ab=bc=10 cm, ac=12 cm, ak⊥bc, cm⊥ab, bn ⊥ac . find: ak, bn, cm.

AK = CN = 9.6 cm

BN = 8 cm

Step-by-step explanation:

AC is the base of the isosceles triangle, so N is the midpoint of AC. CN is 6 cm, so the Pythagorean Theorem tells us the altitude BN is

... BN = √(BC² -CN²) = √(100 -36) = 8 . . . . cm

The area of the triangle is ...

... Area = (1/2)(AC)(BN) = (1/2)(12 cm)(8 cm) = 48 cm²

The other altitudes (AK, CM) are to sides of length 10, so they can be found from the area formula as ...

... 48 cm² = (1/2)·altitude·(10 cm)

... 48 cm²/(5 cm) = altitude = 9.6 cm

Thus we have BN = 8 cm, AK = CM = 9.6 cm.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x