Which is the standard form of the equation of a parabola with a focus of (0, –3) and its vertex at the origin? a. x^2=-12y b. x^2=12y c. y^2=-12x d. y^2=12x

the equation of the parabola is y2=12x

explanation:

the vertex is midway between the focus ad the directrix

so, the vertex is (0,0)

let p=(x,y) be a point on the parabola.

the distance of p from the directrix is equal to the distance from the focus.

x+3=√(x−3)2+(y−0)2

(x+3)2=(x−3)2+y2

x2+6x+9=x2−6x+9+y2

y2=12x

graph{y^2=12x [-10, 10, -5, 5]}

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

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step-by-step explanation: