If f(x) = x 2 + 1 and g(x) = 3x + 1, find 2f(1) + 3g(4).

43

Step-by-step explanation:

We are given two functions: f(x) = x^2 + 1 and g(x) = 3x + 1.

To find 2f(1), firstly find f(1) by substituting 1 in place of x and then multiply the result by 2 to get:

f(1) = (1)^2 + 1 = 1 + 1 = 2

2f(1) = 2(2) = 4

To find 3g(4), find g(4) and then multiply the result by 3 to get:

g(4) = 3(4) + 1 = 12 + 1 = 13

3g(4) = 3(13) = 39

Now add the values for 2f(1) and 3g(4):

2f(1) + 3g(4) = 4 + 39 = 43

answer: a.   one is a factor of every whole number since every number is divisible by itself.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2