Given events g and h: p(g) = 0.46; p(h) = 0.26; p(h and g) = 0.13 a)find the probability of the complement of event (h and g). b)find the probability of the complement of event (h or g).

We are given

P(G)=0.46

P(H)=0.26

P(H∩G)=0.13

(a)

we know that

the probability of the complement of event (H AND G) is

=1-P(H∩G)

so, we can plug value

the probability of the complement of event (H AND G) is

=1-0.13

=0.87Answer

(b)

the probability of the complement of event (H OR G) is

=1-P(H∪G)

so, firstly we will find P(H∪G)

P(H∪G)=P(H)+P(G)-P(H∩G)

now, we can plug value

P(H∪G)=0.26+0.46-0.13

P(H∪G)=0.59

So,

the probability of the complement of event (H OR G) is

=1-0.59

=0.41Answer

answer: a and b

step-by-step explanation:

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.