Match each binomial expression with the set of coefficient of the term obtain by expanding the expression

I   ...  3

II ...  4

III  ...  2

IV ... 1

Step-by-step explanation:

Recall binomial theorem as

(x+y)^n = x^n+nCr x^(n-1)Y++y^n

Using the above we find that

(x+y)^4 = x^4+4x^3+6x^2+4x+1

Hence 4 matches with 1.

Next option 27,54,36,8

are from (3x+2y)^3 because

(3x+2y)^3 = 27x^3+8y^3+18xy(3x+2y)

Option 2 for question 3.

Next is (2x+y)^3 will have 4 terms with coefficients as

8, 12,6,1

So I question for option 4.

The last question 2 = (2x+3y)^4

= (2x)^4+4(2x)^3(3y) + 6(2x)^2(3y)^2+4(2x)(3y)^3+(3y)^4

Hence coefficients are 16,96, 216,216 and 81

I   ...  3

II ...  4

III  ...  2

IV ... 1

step-by-step explanation:

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they go with it happens or they mite give a chance?

step-by-step explanation: