Jon caught four fish that weighed a total of 252 pounds. the kingfish weighed twice as much as the amberjack and the white marlin wrighed twice as much as the kingfish. the weight of the tarpon was 5 times the weight of the amberjack. how much did each fish weigh?

Step-by-step explanation:

Let k, a, m, t represent the weights of the kingfish, amberjack, marlin, and tarpon, respectively. The problem statement tells us ...

Using substitution, we can rewrite the last equation as ...

... (2a) + (a) + 2(2a) + (5a) = 252

... 12a = 252 . . . . . collect terms

... a = 21 . . . . . . . . .divide by 12

Then k = 2a = 42; m = 2k = 84; t = 5a = 105.

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step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204