The area of a rectangular pool is given by the trinomial to 2y^2+y - 3 what are the possible dimensions of a pool. use factoring

2y² + y - 3

(2y+3)(y-1)

2y(y-1) + 3(y-1)
2y² - 2y + 3y - 3
2y² + y - 3

2y + 3 = 0
2y = -3
y = -3/2
y = -1 1/2

y - 1 = 0
y = 1

2y² + y - 3 = 0
2(-3/2)² + (-3/2) - 3 = 0
2(9/4) - 3/2 - 3 = 0
18/4 - 3/2 - 3 = 0
18/4 - (3/2 * 2/2) - 3(4/4) = 0
18/4 - 6/4 - 12/4 = 0
(18 - 6 - 12)/4 = 0
(18 -18)/4 = 0
0/4 = 0
0 = 0

C

Add the cents that add the left overs to get the first number