How does the graph of g(x)=0.25⌊x⌋ differ from the graph of f(x)=⌊x⌋? multiplying by 0.25 compresses the graph of g(x)=0.25⌊x⌋ vertically by a factor of 0.25. multiplying by 0.25 shifts the graph of g(x)=0.25⌊x⌋ down 0.25 unit. multiplying by 0.25 shifts the graph of g(x)=0.25⌊x⌋ up 0.25 unit. multiplying by 0.25 shifts the graph of g(x)=0.25⌊x⌋ right 0.25 unit.

y=|x|  is the base graph

y=|x+b|  this moves it opposite to b = -b units horizontally (left or right)

y=|x| +c this moves it c units vertically (up or down)

y=d|x|  stretches of compresses it by d units  

so 0.23|x| compresses it vertically by 0.25

Its the first choice

Step-by-step explanation:

This compresses the graph vertically by a factor of 0.25.

So for example  if g(x) = 5 the point will move down to 5 * 0.25 =  1.25

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.