I'm having a hard time understandind these, would be appreciated

f(3) = 3^3 - 14*9 + 61*9 - 84 = 0 so 3 is one zero long division of the expression by (x - 3) gives the quadratic x^2 -11x + 28 which = (x - 7)(x-4) so the other zeros are 4 and 7, 3,4 and 7

Basically your answer is 7, 4, and 3

Step-by-step explanation:

5x^3-6x²-59x+12=5x^3-x²-5x²+x-60x+12 =x²(5x-1)-x(5x-1)-12(5x-1) =(5x-1)(x²-x-12) =(5x-1)(x²+3x-4x-12) =(5x-1)(x(x+3)-4(x+3)) =(5x-1)(x+3)(x-4) zeros are

And your answer for this is; 4, -3, 1/5

Hope this helped and good luck :)

(Brainliest is always appreciated)

hi, i am not sure about this one but i think its d,

hope this !