Due today will give anything what is the recursive rule for the sequence? 4.4, 5.8, 7.2, 8.6, 10, … an=an−1−1.4 , where a1=4.4an=an+1+1.4 , where a1=4.4an=an+1−1.4 , where a1=4.4an=an−1+1.4 , where a1=4.4

a_n=a_(n−1)+1.4 , where a_1=4.4

Step-by-step explanation:

Given a sequence as

4.4, 5.8, 7.2, 8.6, 10, …

We find that first term is 4.4

II term = 5.8 = 4.4+1.4

III term = 7.2 = 5.8+1.4

Iv term = 8.6 = 7.2+1.4

V term = 10.0 = 8.6+1.4

i.e. each term is got by adding 1.4 to the previous term.

In other words, this is an arithmetic sequence with I term =4.4 and d = common difference =1.4

I term = a_1 = 4.4

and a_2 = a_1+1.4 and so on.

Hence correct answer is

a_n=a_(n−1)+1.4 , where a_1=4.4

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3