In 2003, troy bought a new car for $33,500 . the car was worth $21,000 in the year 2011. if troy knows that the value of the car depreciated linearly, what was the annual rate of change of the car's value? round your answer to the nearest hundredth if necessary. can someone me?

In 2003, Troy bought a new car for $33,500 . The car was worth $21,000 in the year 2011. If Troy knows that the value of the car depreciated linearly,

Let x be the number of years and y be the cost of the car

Lets assume x=0 for 2003

for 2003, x=0  . so for year 2011 , x= 2011- 2003 = 8

When x=0, y = 33,500

When x= 8, y= 21,000

So two points are (0, 33500) and (8,21000)

To find annual rate of change we find slope because the car depreciated linearly.

Slope = -1562.50

The rate of change of car's value = -1,562.50

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076