Mathematics, 05.07.2019 02:30 AsianAtari9340
Me ! find the number of real number solutions for the equation. x^2 - 18 = 0 a. cannot be determined b. 0 c. 1 d. 2
Answers: 2
![\bf x^2-18=0\implies x^2+0x-18=0 \\\\[-0.35em] ~\dotfill\\\\ \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+0}x\stackrel{\stackrel{c}{\downarrow }}{-18} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{\underline{two solutions}}\\ negative&\textit{no solution} \end{cases} \\\\\\ 0^2-4(1)(-18)\implies 0+72\implies 72\qquad \stackrel{\qquad\uparrow }{positive}](/tpl/images/0052/4794/17f3a.png)
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Me ! find the number of real number solutions for the equation. x^2 - 18 = 0 a. cannot be determined...
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