Solve the equation by completing the square.  ^x2- 12x = -28

x^2 -12 x = -28

(-12/2) ^ 2  =36

x^2 -12 x + 36 = -28 + 36

x^2 -12x + 36 = 8

(x-6)^2 = 8

take the square root of each side

x-6 = sqrt (8)    x-6 = -sqrt (8)  

you get a positive and a negative when taking                                                                 the square root

x= 6 + sqrt (8)  

x = 6 - sqrt (8)

sqrt (8) = 2 sqrt (2)

x= 6 + 2 sqrt (2)

x = 6 - 2 sqrt (2)

x= 6 + 2 sqrt (2)

x = 6 - 2 sqrt (2)

x = 6 + 2√2  and  x = 6 - 2√2

Step-by-step explanation:

Please write the " ^ " symbol between x and 2 here:  x^2 - 12x = -28.

Take half the coefficient of x; here that is -6.

Square this, obtaining 36.

Add 36 to, and then subtract 36 from, x^2 - 12x:  x^2 - 12x + 36 - 36.

Rewrite  x^2 - 12x + 36 as the square of a binomial:  (x - 6)^2.

Then rewrite  x^2 - 12x = -28  as (x - 6)^2 - 36 = -28.

Simplifying, (x - 6)^2 = 8.

Taking the square root of both sides, x - 6 = plus or minus 2√2.

Then the solutions are x = 6 + 2√2  and  x = 6 - 2√2

46.2+112.3

step-by-step explanation:

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step-by-step explanation: