Mathematics, 05.07.2019 06:30 AlexBeWare1210

About 12% of the population of a large country is hopelessly romantic. if two people are randomly selected, what is the probability both are hopelessly romantic/ what is the probability least one is hopelessly romantic?

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Answer from: angryapple1133

Probabilities are used to determine the chances of an event

The probability that both are hopelessly romantic is 0.0144The probability that at least 1 is hopelessly romantic is 0.2256

The given parameters are:

$\mathbf{p = 12\%}$ --- proportion that are hopelessly romantic

$\mathbf{n = 2}$ --- the selected sample

(a) The probability that both are hopelessly romantic

This is calculated as:

$\mathbf{Pr = p^n}$

So, we have:

$\mathbf{Pr = (12\%)^2}$

Express as percentage

$\mathbf{Pr = (0.12)^2}$

$\mathbf{Pr =0.0144}$

Hence, the probability that both are hopelessly romantic is 0.0144

(b) The probability that at least one is hopelessly romantic

First, calculate the probability that none are hopelessly romantic

This is calculated as:

$\mathbf{Pr =(1- p)^n}$

So, we have:

$\mathbf{Pr =(1- 12\%)^2}$

Express as percentage

$\mathbf{Pr =(1- 0.12)^2}$

$\mathbf{Pr =0.88^2}$

$\mathbf{Pr =0.7744}$

Using the complement rule, the probability that at least 1 is hopelessly romantic

$\mathbf{P(At\ least\ 1) = 1 - 0.7744}$

$\mathbf{P(At\ least\ 1) = 0.2256}$

Hence, the probability that at least 1 is hopelessly romantic is 0.2256

Read more about probabilities at:

link

Answer from: raylynnreece4939

If two people are randomly selected, then the probability both are hopelessly romantic=0.0144

If two people are randomly selected, then the probability at least one is hopelessly romantic =0.2256

Step-by-step explanation:

Binomial probability distribution formula :-

$P(x)=^nC_xp^x(1-p)^{n-x}$ , where P(x) is the probability of success in x trials , n is the total number of trials and p is the probability of success.

Given : The probability of population of a large country is hopelessly romantic =0.12

If two people are randomly selected, then the probability both are hopelessly romantic :-

$P(2)=^2C_2(0.12)^2(1-0.12)^{2-2}\\\\=(1)(0.0144)(1)=0.0144$

If two people are randomly selected, then the probability at least one is hopelessly romantic:-

$P(x\leq1)=P(1)+P(2)=^2C_1(0.12)^1(1-0.12)^{2-1}+0.0144\\\\=(2)(0.12)(0.88)+0.0144=0.2112+0.0144=0.2256$

Answer from: Quest

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent

Which statement best describes the association between variable x and variable y? perfect negative

Answer from: Quest

x = 3 ± √(5+y)

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