Two consecutive intergers have a sum of 79, find the intergers

The integers are 39 and 40.

Step-by-step explanation:

Let the smaller integer be x.

The next greater integer is x + 1.

Their sum is x + x + 1.

Their sum is 79, so

x + x + 1 = 79

Solve for x.

2x + 1 = 79

2x = 78

x = 39

x + 1 = 40

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step-by-step explanation:

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.