Find the length of the line segment between the points (-14,-9) and (10,-2).

d= sqrt((y2-y1)^2 +(x2-x1)^2)

  = sqrt((-2+9)^2+(10+14)^2)

   = sqrt((7^2 +24^2)

    = sqrt(49+576)

    = sqrt(625)

    = 25

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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