4ax+3ay+4bx+3by factor by grouping answer= (_ + + _y)

Hey there!!

We have:

... 4ax+3ay+4bx+3by  

Now, let's group these terms.

... 4ax+4bx+3ay+3by

Now, we have grouped these terms. We have two sections.

4ax+4bx and 3ay+by

Now, let's take common term in both these sections.

... 4ax+4bx (The common term is 4x )

Hence, this would become:

... 4x(a+b)

And 3ay+by

(The common term,is 3y )

... 3y(a+b)

Hence, the equation would be :

... 4x(a+b)+3y(a+b)

... (4x+3y)(a+b)

Hence, the blanks are 'a', '4'and '3'

Hope my answer helps!

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step-by-step explanation

2r= 2300

r =1150