Composition functionuse f(x) = x + 2 and g(x) = x2 - 2x1)evaluate f(g(-1))could you explain how to solve this problem? ￣へ￣

well you find g(-1) which is g(-1) = (-1)^2 - 2(-1) = 3

then you shove thawt into f since g(-1)=3

so f(g(-1)) = f(3) = 3+2= 5

in other words f(x) = x + 2 and g(x) = x² - 2x have composition

f(g(x)) = (x² - 2x) + 2

remember in function notation, where ever you see x you replace

e.g. f(x) = x + 2,

f(2) = 2 + 2

f(3) = 3+2

f(x+y) = x+y+2

so f(g(-1)) = g(-1) + 2

the expected value of the random variable : 0, 1 and 2

step-by-step explanation: