Farmer ed has7500 meters of fencing, and wants to enclose a rectangular plot that borders on a river. if farmer ed does not fence the side along the river, what is the largest area that can be enclosed?

7,031,250 m^2

Step-by-step explanation:

We know that:

Area of a rectangle = length x width

Also, since the rectangular plot shares a border with a river so Farmer Ed only needs to fence rest of the three sides therefore, we can write it as:

F = x + 2y

7500 = x + 2y

Solving this equation for x, we get:

x = 7500 - 2y --- (i)

Now substitute this value of x in the Area of rectangle:

Area = (7500 - 2y) * y

Area = -2y^2 + 7500y --- (ii)

The coefficient of -2 means that the largest area will be at:

-7500 / [2 (-2) ] = 1875 so y = 1875

So substituting this value of y in the equation (i) we get:

x = 7500 - 2(1875)

x = 7,031,250 m^2

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.