What can be the last digit of a square of a natural number?

The last digit of the square of a natural number can be 0, 1, 4, 5, 6, or 9.

A natural number is a number resulting from a count of a finite number of things. Thus, integers from 0 are considered natural numbers, since they allow us to represent a certain amount of things.

To determine what can be the last digit of a square of a natural number, this number must be multiplied by itself:

1 x 1 = 1 2 x 2 = 4 3 x 3 = 9 4 x 4 = 16 5 x 5 = 25 6 x 6 = 36 7 x 7 = 49 8 x 8 = 64 9 x 9 = 81 10 x 10 = 100

Thus, the last digit of the square of a natural number can be 0, 1, 4, 5, 6, or 9.

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Any of {0, 1, 4, 5, 6, 9}

Step-by-step explanation:

The squares of the digits 0–9 are ...

0, 1, 4, 9, 16, 25, 36, 49, 64, 91

The last digit of a square must be the last digit of one of these:

... {0, 1, 4, 5, 6, 9}

_____

Comment on the problem

You will see that the squares of 5 and 6 end in 5 and 6, respectively. Such a number is called an automorph. The last half of its square is the original number. These can be extended indefinitely, usually according to a simple rule. The 3-digit automorph ending in 6 is 376. (376² = 141,376). The 5-digit automorph ending in 5 is 90625. (90625² = 8212890625)

Automorphs can also be found in number bases other than base-10.

Number nine is f(x)= 40x : ) hoped i ya

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )