Arectangle's length is 4 feet more than it's width. if the area of the rectangle is 396 square feet, what is its width, in feet?

18 feet

Step-by-step explanation:

Let the width of the rectangle to be x.

Therefore, the length which is 4 feet more than the width will be = x + 4

We know that the Area of a rectangle = L x W, so we will substitute the values of area, length and width in it to get:

Area = L x W

396 = (x + 4) (x)

396 = x^2 + 4x

x^2 + 4x - 396 = 0

Now we will factorize this quadratic equation:

x^2 + 4x - 396 = 0

x^2 + 22x - 18x -396 = 0

x (x + 22) - 18 (x + 22) = 0

x = -22 (ignore) and x = 18

So width is 18 feet and by adding 4 to it we can know the length which is 18 + 4 = 22 feet.

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