Hurry 30 pts what is the equation of the graphed line written in standard form? a. 3x + y = –5 b. x + 3y = –5 c. 3x – 5y = –15 d. 5x – 3y = 15

D

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 0 ) and (x₂, y₂ ) = (0, - 5 )

m = =

line crosses y-axis at (0, - 5 ) hence c = - 5

y = x - 5 ← in slope-intercept form

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

rearrange slope-intercept form into standard form

multiply all terms by 3

3y = 5x - 15 ( subtract 3y and add 15 to both sides )

5x - 3y = 15 ← in standard form → D

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

step-by-step explanation: