The weights of a particular size of boxes of apple cinnamon cheerios are approximately normally distributed with mean weight 23.3 oz and standard deviation 0.2 oz. they wish to reject any box of cereal that weighs less than the listen weight of 22.7 oz. based on the empirical rule (68/95/99.7), what percentage of cereal boxes will general mills reject?

0.15%, or 15/100 of 1%, or 3/20 of 1%

Step-by-step explanation:

68% of the data lies within 1 standard deviation of the mean (23.3 oz), or between 23.1 oz and 23.5 oz.

95% of the data lies within 2 std. dev. of the mean, or between 22.9 oz and 23.3 oz.  

99.7% of the data lies within 3 std. dev of the mean, or between 22.7 oz. and  23.1 oz.

The remaining area under the curve is 100% - 99.7%, or 0.3%,  Only half of this, or 0.15%, is to the left of 22.7 oz.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

step-by-step explanation:

answers available in this download

(pearson%2c%25202012)%2520bbs.pdf& usg=aovvaw1obmtxnfghfgxhx0urh_je