Apicture has a height that is 4/3 its width. it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement?

12 in wide by 16 in high

Step-by-step explanation:

Let w represent the width of the enlarged picture. Then the height is (4/3)w, and the area is the product of width and height:

... area = width × height

... 192 in² = w × (4/3)w . . . . substitute the given information

... 192 in² = (4/3)w² . . . . . . . simplify

... 144 in² = w² . . . . . . . . . . . multiply by 3/4

... 12 in = w . . . . . . . . . . . . . .take the square root

... height = (4/3)w = (4/3)(12 in) = 16 in

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.