The arch of the sydney harbor bridge is appropriate 500 meters long and 85 meter high. what quadratic function models the curve of the arch? assume the arch starts at (0,0).

  Equation of arch,   y= (-1.36 * 10⁻³)x²+0.68 x

Explanation:

 General form of quadratic equation is y = ax²+bx+c

  The starting point is (0,0)

             0 = a * 0² + b * 0 + c

             c = 0

  So  y = ax²+bx

  The ending point of arch is (500,0), since the length of arch is 500 m.

      0 = a* 500² + b * 500

     500 a + b = 0    Equation 1

 The mid point of arch is (250, 85), since the height of arch is 85 m.

        85 = a * 250² + b * 250

         12500 a + 50 b = 17    Equation 2

 Equation 1 x 50,

      50*( 500 a + b) = 50*0

      25000 a + 50 b = 0    Equation 3

Equation 3 - Equation 2

      25000 a + 50 b - ( 12500 a + 50 b) = 0 - 17

      12500 a = -17

      a = -1.36 x 10⁻³

Substituting in equation 1,

     500 x (-1.36 x 10⁻³)+ b = 0

     b = 0.68

 So equation of arch,   y= (-1.36 * 10⁻³)x²+0.68 x

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation: