(1 point) a random sample of 600 movie goers in flagstaff found 252 movie goers who had bought popcorn on their last visit. find a 95% confidence interval for the true percent of movie goers in flagstaff who have bought popcorn on their last visit. express your results to the nearest hundredth of a percent.%

Answer-

A 95% confidence interval for the true percent of movie goers is 36.41% to 44.25%

Solution-

Given,

n = 600 (sample size)

x = 252 (number of people who bought)

Confidence interval = 95%, so z = 1.96

We know that,

where,

M = sample mean

Z  = Z statistic determined by confidence level

SE = standard error of mean

Calculating the values,

from the tables

Putting all the values in the formula,

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5

answer: 3.26019516

step-by-step explanation: