Abakery sells doughnuts for $1.00, muffins for $1.50 bagles for $1.20. the bakery makes three times as many doughnuts as bagels. if the bakery sells all 130 items in stock, they earn a total of $150. how many items are in stock at the bakery? justify your answer. [hint: use d for the # of doughnuts, m for the # of muffins and b for the # of bagels.]

ANSWER

As given in the question

use D for the number of doughnuts,

M for the number of muffins and B for the number of bagels.

 The bakery makes three times as many doughnuts as bagels

equations becomes

D = 3B

bakery sells all 130 items in stock

equations becomes

D + B + M = 130

Bakery earn a total of $150

equations becomes

1.00D + 1.50M+ 1.20B = 150

On simplier terms

1D + 1.5M + 1.2B = 150

three equation are become in the form

D = 3B

D + B + M = 130

1D + 1.5M + 1.2B = 150

subract D + B + M = 130 equation from  1D + 1.5M + 1.2B = 150

1D -1D + 1.5M -M + 1.2B -1B = 150 -130

0.5M + 0.2B = 20

in simple form

5M + 2B = 200

Put D = 3B in the equation D + B + M = 130

we get

4B + M = 130

Now multiply 4B + M = 130 by 5 and subtracted from 5M + 2B = 200

5M - 5M + 2B - 20 B = 200 - 650

-18 B = - 450

B = 25

Put this value in the D = 3B

we get

D = 25×  3

  = 75

Put the value of D and B in the equation  D + B + M = 130 .

75 + 25 + M= 130

130 - 100 = M

M = 30

items are in stock at the bakery is doughnuts = 75 , muffins = 30 ,  bagels = 25.

Hence proved

50- 250 is correct i did that one too

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: