Soon will mark brainliest write the equation of the line parallel to the given line and passing through the given point. y=1/3x−1 through (6,3)

y = (1/3)x + 1

Step-by-step explanation:

I'll assume that you meant y = (1/3)x - 1.  This line has the slope 1/3.  Write out the stope-intercept form y = mx + b and subst. (1/3) for m, 3 for y, 6 for x and calculate b:

3 = (1/3)(6) + b, or 3 = 2 + b.  Thus, b = 1, and we have the new equation

y = (1/3)x + 1.  This is parallel to y = (1/3)x - 1 and passes thru (6,3):  3 = (1/3)(6) -1 is true.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

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step-by-step explanation: